Variation 2 · answer guide
Vector motion — A perpendicular-velocity time
Question
For and , find positive t when they are perpendicular.
This practice question was inspired by Question 14(b) in the 2025 NSW HSC Mathematics Extension 1 examination, © NESA. It is an original TestMum variation that practises the same mathematical idea, not an official NESA question.
Step by step
- Set up the solution: differentiate position to get velocity and acceleration, then translate the angle condition into a dot product.Perpendicular vectors have dot product zero.
- Simplify the previous line carefully, keeping exact values where possible..
- Finish the calculation, then check that the result meets the question’s conditions., so .
- State the final answer clearly in the form the question requested.Final answer:
Common mistake: changing so many features that the new example no longer tests the same mathematical idea.
Verification: Substitution makes the dot product zero.
Any mark labels are a TestMum study aid, not an official NESA marking allocation.
← Back to 2025 HSC Extension 1 paper Question 14(b)