← 2023 HSC Extension 1 questions

2023 HSC Mathematics Extension 1

Question 11(b):
Combinatorics

2 markscombinatorics

In how many different ways can all the letters of the word CONDOBOLIN be arranged in a line?

How to recognise this question

Question type: combinatorics

  • The command and notation point to combinatorics.
  • The requested response is a worked solution.

How to handle it: count a simple unrestricted set first, then add or subtract the arrangements that break the condition.

Watch out: Do not select a formula until its domain, interval, sign and units match the question.

Step-by-step answer

  1. CONDOBOLIN has letters: C, O, N, D, O, B, O, L, I, N.
  2. Letter multiplicities: O appears times, N appears times; other letters once.
  3. Number of distinct linear arrangements: .
  4. NESA: 2 marks for correct solution; 1 mark for dividing by a relevant number, or equivalent merit.

Common mistake: choosing a familiar formula before checking that its conditions, signs, interval and units match this question.

The paper records 2 total marks for this group. Where the official marking guide provides useful partial-credit criteria, those criteria are stated in the steps above.

Try your hand at it again by answering these questions

Question 1

How many distinct linear arrangements of the letters in MISSISSIPPI are there?

See the step-by-step answer guide →

Question 2

Find the number of distinct arrangements of the letters in BANANA.

See the step-by-step answer guide →

Question 3

How many linear arrangements of VECTOR are there?

See the step-by-step answer guide →